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Factoring Help |
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| Feb24-13, 05:56 PM | #1 |
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Factoring Help
Hey everyone first time poster here, I need help with some factoring of cubes. I know this might tie closely to Diophantine equations but here goes.
Under what condition is the expression x^3+y^3+z^3 factorable? Where x,y,z are positive whole numbers. |
| Feb25-13, 02:15 PM | #2 |
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well it seems to factor if x=1, y=2, z=3, and if x=y=z ≥ 2, and more generally if gcd(x,y,z) > 1.
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| Feb27-13, 04:34 PM | #3 |
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My bad for not stating before. Let's assume the gcd(x,y,z) =1 and gcd(x,y)>1
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