| New Reply |
Second Order Equation - Change of variables |
Share Thread | Thread Tools |
| Feb28-13, 10:56 AM | #1 |
|
|
Second Order Equation - Change of variables
Hello there,
I am facing the second order ODE in the unknown function $$y(t)$$ $$ \ddot{y} = a \dot{y} y - b \dot{l} l - c\dot{l} + d$$ $$a, b, c, d$$ positive constants, such that $$ \frac{a}{b} = \frac{d}{c}$$ I would like to understand more about it before relying on numerical methods. So far, I have only determined that the long term solution as $$t \to 0$$ is a linear function, $$y(t) = \frac{a}{b}t$$. If the boundary condition on $$\dot{y}$$ is zero, I get interesting transient behaviour. If the boundary condition on $$\dot{y}$$ equals $$ \frac{a}{b}$$ i get, as expected, a linear solution, which though starts getting very wiggly and wildly oscillating (stiff equation?). Is there some change of variable, some tecnique, some trick I could use to reduce my equation in a form friendlier for analytic investigations? Many thanks |
| Feb28-13, 02:20 PM | #2 |
|
|
what is l in the ode for y(t)? Is it a second dependent variable as in l(t)
|
| Mar1-13, 04:46 AM | #3 |
|
|
I made a mistake in writing the equation down, sorrry for the confusion created.
The ODE in the unknown $$y(t)$$ looks like $$\ddot{y}= a \dot{y} t - b y \dot{y} -c \dot{y} + d$$ with $$ \frac{a}{b} = \frac{d}{c}$$ (the costants ratios allow the linear solution $$y (t) = \frac {a}{b} t$$, B.C. allowing) Thanks |
| New Reply |
| Thread Tools | |
Similar Threads for: Second Order Equation - Change of variables
|
||||
| Thread | Forum | Replies | ||
| Change of variables in a second order SDE | Differential Equations | 1 | ||
| Using change of variables to change PDE to form with no second order derivatives | Calculus & Beyond Homework | 1 | ||
| Equation with two second order variables | Calculus & Beyond Homework | 1 | ||
| Change of variables in Seocnd order ODES | Differential Equations | 1 | ||
| 1-D wave-equation and change of variables | Calculus & Beyond Homework | 2 | ||