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how many bit strings of length 8 contain either three consecutive 0s or four consecutive 1s?
The discussion focuses on calculating the number of bit strings of length 8 that contain either three consecutive 0s or four consecutive 1s using the principle of inclusion-exclusion. The method involves adding the count of strings with three consecutive 0s to those with four consecutive 1s, while subtracting the overlap where both conditions are met. This approach provides a systematic way to solve the problem efficiently.
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