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[SOLVED] Simple Antiderivative |
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| Oct5-05, 10:31 PM | #1 |
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[SOLVED] Simple Antiderivative
How would I compute the antiderivative of
[tex]\int \sqrt{1-\frac{x^2}{2}}[/tex] It looks familiar, but I can't quite remember how... |
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| Oct5-05, 10:46 PM | #2 |
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Put
[tex]x=\sqrt{2} \sin u[/tex] and go from there. |
| Oct6-05, 03:14 AM | #3 |
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U can also put the Riemann measure on [itex]\mathbb{R} [/itex] : [itex] dx [/itex].
![]() Daniel. |
| Oct6-05, 01:16 PM | #4 |
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[SOLVED] Simple Antiderivative
Ah yes, of course. Thanks.
Quick follow-up: [tex]\int\log|\sqrt{1-x^2}+x|[/tex] |
| Oct6-05, 09:59 PM | #5 |
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I think that integrand is related to an inverse hyperbolic trig function... but I'd have to play around with it to work out which one. Maybe somebody else...
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| Oct6-05, 10:03 PM | #6 |
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Perhaps it simply cannot be expressed algebraically?
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| Oct6-05, 10:07 PM | #7 |
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I love Mathematica ![]() Alex |
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