## Irrational numbers question.

Just wondering, if you group decimal places of an irrational number, lets say into sequences of groups of 10, for example,

if k is irrational 4.4252352352,3546262626,224332 (I made that up)

they you group (.4252352352) (3546262626) (and so on)

then my question is that the probability of any number between 0-9 appearing the group is simply 1/10 or .1
 Mentor Blog Entries: 9 This depends on the number, the property you describe is called Normal. If an irrational number is normal then it meets your condition. I do not know how common the property is. Nor am I familiar with how it is proven. I have heard that PI may be normal.
 Recognitions: Homework Help Science Advisor First, the number you wrote is not irrational! :) With regard to the probability of any particular digit appearing in any group of 10, that assumes the digits are "random" which I don't believe you would be able to prove. Moreover, here's an example of an irrational number for which the probability of any of the digits 2..9 appearing is zero: k = 0.101001000100001 ... with the obvious pattern of digits. Also, the probabilities of finding zeros and ones are not equal.

Recognitions:
Homework Help