- #1
BLUE_CHIP
OK. I've had a little break from my studdies and need some help with this...
[itex]I_n(x)=\int\limits_0^x \tan^n{{\theta}}{{d\theta}},n\leq{0},{{x}}<\frac{\pi}{2}[\latex]<br /> <br /> By writing [itex]\tan{\theta}[\latex] as [itex]\tan^{n-2}{\theta}\tan^2{\theta}[\latex], or otherwise, show that<br /> <br /> [itex]I_n(x)=\frac{1}{n-1}\tan^{n-1}{x}-I_{n-2}(x), n\leq{2},x<\frac{\pi}{2}[\latex]<br /> <br /> Hence evaluate [itex]\int\limits_{0}^{\frac{\pi}{3}}\tan^4{\theta}d\theta[\latex], leaving your answers in terms of [itex]\pi[\latex]<br /> <br /> Thanks (Goddam further maths)<br /> <br /> AHHHH some one edit my post and get this bloody tex to work! pls[/itex][/itex][/itex][/itex][/itex][/itex]
[itex]I_n(x)=\int\limits_0^x \tan^n{{\theta}}{{d\theta}},n\leq{0},{{x}}<\frac{\pi}{2}[\latex]<br /> <br /> By writing [itex]\tan{\theta}[\latex] as [itex]\tan^{n-2}{\theta}\tan^2{\theta}[\latex], or otherwise, show that<br /> <br /> [itex]I_n(x)=\frac{1}{n-1}\tan^{n-1}{x}-I_{n-2}(x), n\leq{2},x<\frac{\pi}{2}[\latex]<br /> <br /> Hence evaluate [itex]\int\limits_{0}^{\frac{\pi}{3}}\tan^4{\theta}d\theta[\latex], leaving your answers in terms of [itex]\pi[\latex]<br /> <br /> Thanks (Goddam further maths)<br /> <br /> AHHHH some one edit my post and get this bloody tex to work! pls[/itex][/itex][/itex][/itex][/itex][/itex]
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