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integral and its largest value

 
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Dec3-05, 09:36 AM   #1
 

integral and its largest value


hello..could you please help me to solve this problem?

Along what curve of the family y=x^n does the integral
int{(25xy-8y^2)dx} attain its largest value? and the boundaries for the integral is from (0,0) to (1,1)

thank you..
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Dec3-05, 10:32 AM   #2
 
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Any thoughts on this problem? Maybe just evaluating the integral along the curve x^n?
Dec3-05, 08:40 PM   #3
 
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Along what curve of the family y=x^n does the integral
int{(25xy-8y^2)dx} attain its largest value?
\ doesn't mean a whole lot to me. Do you mean "where does x^n intersect the integral of 26xy- 8y^2 dx with the largest y value?
Dec3-05, 09:15 PM   #4
 

integral and its largest value


Quote by nepenthe
hello..could you please help me to solve this problem?
Along what curve of the family y=x^n does the integral
int{(25xy-8y^2)dx} attain its largest value? and the boundaries for the integral is from (0,0) to (1,1)
thank you..
Is this what you're looking for ??

[tex] \begin{gathered}
y = x^n \Rightarrow 25xy - 8y^2 = 25x^{n + 1} - 8x^{2n} \hfill \\
\frac{d}
{{dn}}\left[ {\int\limits_0^1 {\left( {25x^{n + 1} - 8x^{2n} } \right)dx} } \right] = \frac{{16}}{{\left( {2n + 1} \right)^2 }} - \frac{{25}}{{\left( {n + 2} \right)^2 }} = 0 \Rightarrow \frac{4}{{2n + 1}} = \frac{5}{{n + 2}} \Rightarrow n = \frac{1}
{2} \hfill \\
\therefore {\text{Curve is }}y = \sqrt x \hfill \\
\end{gathered} [/tex]

(If you allow 'n' to be a rational number, that is )

---?Though I'm not sure this is what you're looking for ?
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