Centripetal Acceleration lab graph

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SUMMARY

The discussion centers on the relationship between centripetal acceleration and angular velocity (omega) in a lab experiment involving circular motion. Participants clarify that centripetal acceleration, calculated using the formula a = v²/r, is distinct from gravitational force and does not equal acceleration due to gravity (g). The lab involves spinning a string with a stopper and weights, requiring participants to graph centripetal acceleration against angular velocity. The conclusion emphasizes that while centripetal acceleration is necessary for maintaining circular motion, it is not equivalent to gravitational acceleration.

PREREQUISITES
  • Understanding of centripetal acceleration and its calculation (a = v²/r)
  • Familiarity with angular velocity (omega)
  • Basic knowledge of forces in circular motion
  • Experience with graphing scientific data
NEXT STEPS
  • Study the relationship between centripetal force and mass in circular motion
  • Learn how to derive centripetal acceleration from angular velocity
  • Explore the implications of gravitational force on objects in circular motion
  • Investigate real-world applications of centripetal acceleration in engineering
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of circular motion and centripetal acceleration in laboratory settings.

sarujin
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I have a lab that needs a graph, and my calculations seem logical, but I need some affirmation. In this lab we spun a string with a stopper attached at one end and some weights at the other end. We had to keep a part of the string at the same point while spinning and therefore it moved at a constant angular velocity, right? ( http://www.richardson.k12.tx.us/schools/phs/staff/academ/klindsay/Web/lindsay/Pre-AP/MomRot/Lab%20Circ%20Mot.htm ) is the lab, if you need more explanation of the lab. In our calculations we have to graph Centripetal Acceleration vs. omega, the angular velocity. Using the equation F = ma... the force is weight (pulling on the stopper spinning), which is mg. Then mg = ma, then g = a.

In other words, if something is going at a constant velocity around your head in a circle and not falling, centripetal acceleration equals acceleration due to gravity?

Thanks!
 
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If centripetal acceleration equals acceleration due to gravity, then it would stay where it was, in a circle (because its centripetal acceleration)?
 
Originally posted by sarujin
In other words, if something is going at a constant velocity around your head in a circle and not falling, centripetal acceleration equals acceleration due to gravity?

a = v^2/r

centripetal acceleration has absolutely nothing to do with gravitational force.
 

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