
#1
Dec603, 01:15 AM

P: 34

This is a classical mechanics question requarding circular motion. I understand that centripetal force causes objects to accelerate toward the center of the circular path they travel in, but how does this apply to objects traveling on the outside of a circle? I have come to understand that if an object is travelling within a loop, (with enough v) it's natural tendency is to remain on the inner edge of that circle, since its velocity is directed tangentially, and the centripetal acceleration is directed toward the center of the circle. But my question is this: would that same object be pulled toward the center of the circle if it were travelling on the outside of the loop? Say for example, a car is driving over a hill that has a circular shape. If Fr=mv^2/r ( in this case since its travelling on the outside), then would we consider the centripetal accel. to be inward, especially when, giving enough velocity, this car would take off and leave the circle (until gravity pulled it back down, that is)? Conceptually, how is the acceleration (ar) directed toward the hill's center when the centripetal force seems to have little effect on the car at this point?




#2
Dec603, 03:45 AM

Mentor
P: 7,291

Frankly it is rather difficult to find your question among the verbiage.
To maintain a circular path a centripetal force is required. A car does not always stay on the outside of circular loop because there is NO centripetal force to keep it there. A centripetal force is not present the instant something is curved, the force must be provided by some mechanism. When the car is on the inside loop, the track provides the centripetal force, there is no corresponding force when the car is on the outside of the loop. So if gravity is not sufficient to provide the force the car will leave the track. Does that help? 



#3
Dec603, 05:17 AM

Mentor
P: 40,878

Let me add a few comments to Integral's answer.




#4
Dec603, 09:08 AM

Sci Advisor
P: 2,507

Centripetal confusion
Within the Event Horizon of a Black Hole, centrifugal force works in the opposite dsrection from common experience. This means that orbitting at a high rate of speed around the center generates a force pushing one toward the center, rather than away.
Does this mean that within the EH, a centrifugal force becomes centripedal, or is it still considered centrifugal force with a reversed vector value or something like that? Just a matter of terminology, but I'd be interested in knowing the answer. 



#5
Dec603, 12:09 PM

Mentor
P: 7,291

Lurch,
That is the first I have heard of that phenomena. Does it connect to the concept of closed geodesics, which I believe occur inside the EH. I am sure that once you have crossed the EH you have entered the singularity, therefore you must be very careful about application of normal laws of physics. 



#6
Dec603, 02:51 PM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,881

Circles do NOT HAVE "inner" and "outer" edges. Centripetal force and acceleration applies to any object moving in a circle. It is not a question of "inside" or "outside".




#7
Dec603, 03:57 PM

Sci Advisor
P: 2,507





#8
Dec703, 08:10 PM

Sci Advisor
P: 2,507

Well, I found this page that makes refference to the artical, including the issue in which the article is located (March 1995).
Doesn't include any of the article, though. 



#9
Dec803, 10:54 PM

P: 34

arial
Thanks for the replies. I think I understand what the term centripetal force means now. It is only a way of describing forces as they affect objects in motion and cause them to move in circular paths. What I forgot was that centripetal force can take on diffrent forms, like tension, gravity, and so on. Now, if I've got this right, you're saying that centripetal force is only as strong as the force causing it. So back to my car on a hill analogy, if that car's engine creates enough force, then it will leave the hill because gravity (the centripetal force at the time), is not strong enough to keep it on it's circular path... [a)] 


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