## Help Deriving the equation Ek=1/2mv^2

Ok these are the equations im allowed to use.
Ep=mg(delta)h
w=fd
v_av=(delta)d/(delta)t
(delta)d=v1(delta)t^2 + 1/2a(delta)t^2
V2=V1^2 + 2a(delta)d
w=work done(j)
f=force(newtons)
d=distance(m)
v_av=average velocity
t=time(secs)
v2=final velocity
v1=initial velocity
a=acceleration

Ok, i havent done anything so far, because I dont know where to start. Im not asking anyone to solve this for me, i'm just asking for some helpful clues
thanks
 Recognitions: Gold Member You could use energy conservation with the potential energy and use kinimatics to find the final speed after a change in height, using that you should get the same answer that you would have gotten with KE so you would be able to derive it. (I hope that was clear) But thats probably cheating, are you alowed to use cal ? If so than just sum up all of the work done over an interval.
 Ok, first question, where does the Ek come from. It is not in any other equation, doesnt it have to be in order for me to derive i?

## Help Deriving the equation Ek=1/2mv^2

anyone know?
 Recognitions: Gold Member Homework Help Using Newton's Law's you can derive the conservation of mechanical energy. In essence you can derive the expression, 1/2mv^2 + mgh = 0. You then define 1/2mv^2 as kinetic energy. Is this what your trying to do?

 Quote by G01 Using Newton's Law's you can derive the conservation of mechanical energy. In essence you can derive the expression, 1/2mv^2 + mgh = 0. You then define 1/2mv^2 as kinetic energy. Is this what your trying to do?
i dont fully understand that part