Areaby blanny Tags: None 

#1
Jan2406, 09:19 PM

P: 2

Gold, which has a mass of 19.32g for each cubic centimeter of volume, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber.
a) If the sample of Gold, with a mass of 27.63 g is pressed into a leaf of 1.000 micrometer thickness, what is the area of the leaf? Would it be correct to use 27.63g / 19.32g = cubic centimeters? I don't think this would be right because it doesn't take into account the 1.000 micrometer... b) If, instead the Gold is drawn into a cylindrical fiber with radius 2.500 micrometers, what is the length of the fiber? What equations would I need to solve this problem? Thanks, this problem has been really bugging me. blanny 



#2
Jan2506, 12:11 AM

Sci Advisor
HW Helper
P: 3,149

Avoid being sloppy with units: grams divided grams is dimensionless.
Given the density and the mass you can determine the volume of the gold (again, watch those units!). The principle you seem to be missing is that the volume of the gold remains unchanged. In (a) the product of the thickness times the area is the volume and in (b) the crosssectional area of the cylinder times its length is also the volume. 



#3
Jan2506, 12:15 AM

Sci Advisor
PF Gold
P: 1,542

27.63g / 19.32 g, the grams cancel and you're left with a unitless number of 1.430 But 19.32 is not grams. It is "grams for each cubic centimeter" or g/cc aka g/cm^3 Use the correct units and look at the units in your answer: 27.63g / (19.32 g/cc) . The grams cancel. The cc is the denominator of a denominator, which puts it in the numerator, and you get 1.430 cc. So you were correct in your assumption that the answer would yield cubic centimeters. Additional formulas needed: Area: length x width Volume: length x width x height or since lenth x width = area Volume = area x height for part b you will need the formula for volume of a cylinder: area of a circle x height area of a circle = pi x radius^2 



#4
Jan2506, 12:21 AM

Sci Advisor
PF Gold
P: 1,542

Area
Tide beat me to it in pointing out your units
You gotta love this forum! Welcome. 


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