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Constants |
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| Jan30-06, 07:57 PM | #1 |
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Constants
Given a, b are constants and lim x approch 1, a root x+3 - b all over x-1 equals 1. Find a and b
No clue how to answer this, but this is what I think i can do a) get rid of the sqrt b) apply limit See, the problem is I have to unknows so i dont know what to do |
| Jan30-06, 08:15 PM | #2 |
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Is this your problem?
[tex]\lim_{x\rightarrow{1}} \frac{a\sqrt{x+3}-b}{x-1}=1[/tex]? |
| Jan30-06, 08:36 PM | #3 |
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Recognitions:
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You get a simple linear relationship between a and b. ---(1) Now you can use L'Hopital's Rule to evaluate a limit of the form 0/0. So differentiate both numerator and denominator. You know that the quotient of these two is also going to be 1 at the limit x->1. So set x = 1 in that. The b term would have vanished, so you can now solve for a. Put that back in equation (1) and work out b, you're done. |
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