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What do you do if your exact equation isn't exact? and they give u an Integrating F 
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#1
Feb106, 03:57 PM

P: 1,629

Hello everyone I understand how to solve exact equations, but what happens when they arnt' exact? I'm confused on what i'm suppose to do! Does anyone feel like explaning hte process to me, if given an integrating factor/> or give me a website? Here is my problem:
Check that the equation below is not exact but becomes exact when multiplied by the integrating factor. Integrating Factor: Solve the differential equation. You can define the solution curve implicitly by a function in the form ? Thank you! 


#2
Feb106, 04:45 PM

Math
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PF Gold
P: 39,308

Do you understand what an "integrating factor" is?
If a differential equation is not exact then there always exists some function f(x,y) so that multiplying the equation by it makes it exact. Unfortunately, it's most often very difficult (if not impossible) to find that integrating factor! In this case your equation is x^{2}y^{3}dx+ x(1+ y^{2})dy= 0. Yes, that is NOT exact because (x^{2}y^{3})[sub]y[sub]= 3x[sup]2[sup]y^{2} which is not the same as (x(1+ y^{2}))_{x}= 1+y^{2}. Fortunately, you were told that [itex]\frac{1}{xy^3}[/itex] is an integrating factor. That means that multiplying the equation by that: (1/xy^{2}){x^{2}y^{3}dx+ x(1+y^{2})dy = ydx+ (1+y^{2})y^{2})dy= 0. Is that exact? It certainly should be! If it is exact can you solve it? 


#3
Feb206, 07:37 PM

P: 1,629

OOoo!!! Awesome, thanks alot IVEY as always! It worked great! I got:



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