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Magnetic Field and Electric field outside a long solenoid |
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| Feb5-06, 01:40 PM | #1 |
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Magnetic Field and Electric field outside a long solenoid
Hello,
The question goes like this: A long solenoid has n turns per unit length and carries a current given by I=I₀sinωt. The solenoid has a circular cross section of radius R. Find the induced electric field at a radios r from the axis of the solenoid for (a) r<R (b) r>R Well, i got the first part as E=μRēNēωI₀cos(ωt)/(2Rl). Does this looks like it? For the second bit, i found it as zero. But i am not really sure. And if it is zero, What should i say? |
| Feb7-06, 03:26 PM | #2 |
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Hello there,
You'll have to excuse me because I'm not using the greek symbols. (a) r<R, int(E.dl)=-d(B.Area)/dt (definition of induced emf) take loop around E.2*pi*r = -pi*(r^2)*mu*n*I*omega*cos(omega*t) E= -(mu*n*I*omega*r*cos(omega*t))/2 is the induced field inside solenoid. Your answer is close but use r instead of R (since we are inside). (b) r>R, outside You are confusing with the case when magnetic field is zero outside long solenoid due to cancellations between field due to currents in successive & opposite loops. In this case, (r>R...remember loop is longer) E*2*pi*r = -pi*(R^2)*mu*n*I*omega*cos(omega*t) (remember flux is over an area defined by pi*(R^2)) E = -(mu*n*I*omega*(R^2)*cos(omega*t))/ (2*r) is the induced electric field outside. Hope that helps, Rama |
| Feb7-06, 03:54 PM | #3 |
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Mentor
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Are you sure they are asking about Electric fields? That doesn't make much sense. More often, you will be asked to solve for the magnetic field as a function of radius for the solenoid....
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| Feb11-06, 06:57 PM | #4 |
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Magnetic Field and Electric field outside a long solenoid
Yea, i m asked to find electric field. And i just found out this is one of the question found from the textbook. And yes, thats the correct answers! but i am still not sure why it is not zero. isnt that when theres no magnetic field, theres no electric field as well?
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| Feb11-06, 08:10 PM | #5 |
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darkar,
To understand why there is an electric field outside the solenoid, just think about Faraday's Law. If you draw a loop around the solenoid, the magnetic flux through the loop is changing as a function of time, right? Even though there is no magnetic field outside the solenoid there is still a changing magnetic flux (from the field inside the solenoid). What does this tell you about the electric field? |
| Feb12-06, 10:59 AM | #6 |
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Yea, thats amaze me. Why can there be magnetic flux but no magnetic field. So lif theres magnetic field, the magnetic flux is constant?
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