Calculus review!

by hodeez
Tags: calculus, review
P: 28
Hi guys, I have a calculus test tomorrow and it'll be great if I can recieve some answers + explanations! my review sheet is attached. if this is breaking the rules im sorry.

hope this actually helps some other people too
Attached Files
 reviewsheet.doc (39.5 KB, 29 views)
 P: 28 for #1 i got 3x^2-sin(xy^2)*2xy [dy/dx]*y^2 whadaya thinks?
 P: 28 for #2) its log(x)/log4 b)then graph it with my TI89 then find the deriv @ .4 at work right now so no calculator on me =) btw: does the TI89 have a test function == like the ti86?
 P: 28 Calculus review! #3) f'(x)=2+cosx so we have to prove f'(x) is constantly positive or negative.. but how would we approach that?
HW Helper
P: 2,537
 Originally posted by hodeez #3) f'(x)=2+cosx so we have to prove f'(x) is constantly positive or negative.. but how would we approach that?
What's the minimum of cos(x) (assuming x is real)
P: 28
 Originally posted by NateTG What's the minimum of cos(x) (assuming x is real)
sorry im not quite following you. on the y axis it is -1, and on the x it can be -infinite. please correct me if im wrong
 Sci Advisor HW Helper P: 2,537 So, if the minimum value of cos(x) is -1, what is the minimum value of 2+cos(x)?
 P: 28 lol wow i feel so dumb thanks onward to the next question after i finish some quick job for my boss.
 P: 28 i got x-4=y^3+y so turn my ti89 to parametric mode and y1 = t^3+t y2= -1 right? (since its g(3) 3-4 = -1) then i trace for a zero?
 P: 28 just came back from my test and i got confused on a question... find the deriv of x+sin(xy) i got (-sec(x)-y)/x but the calc gave me 1 thanks to all the people that replied and (attempted to) help
 P: 658 d/dx{x+sin(xy)} = 1 +cos(xy)[xdy/dx+y]
 P: 28 oh my goddd what did i do!?! i messed up.. oh wells thanks himanshu121 for reminding me of my errror

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