Velocity and Total Distance Table for Stone Dropped from Tall Building

[celect]

My question I don't understand how to add a colums for total distance.

Construct a table of values of velocity and total distance fallen at the end
of each half-second during the first 5 seconds for a stone at rest dropped
from a very tall building. Include columns for time, velocity, and total
distance


Time of Fall Velocity Aquired Distance
(seconds) (meters/seconds (meters/seconds
_______________________________________
0--------------------- 0---------------------0
0.5-------------------4.9--------------------1.225m/s
1--------------------- 9.8-------------------4.9m/s
1.5-------------------14.7-------------------11.025m/s
2 ------------------- 19.6------------------19.6m/s
2.5------------------24.5--------------------30.625m/s
3 -------------------- 29.4------------------44.1m/s
3.5-------------------34.3-------------------60.025m/s
4--------------------- 39.2------------------78.4m/s
4.5-------------------44.1-------------------99.225m/s
5--------------------- 49--------------------122.5m/s

 

[Doc Al]

Originally posted by celect
My question I don't understand how to add a colums for total distance.

I know you know how to find the distance an object falls as a function of time. Use the basic kinematics equation for accelerated motion.

(You won't need to add columns.)

 

[celect]

Originally posted by celect
My question I don't understand how to add a colums for total distance.

Construct a table of values of velocity and total distance fallen at the end
of each half-second during the first 5 seconds for a stone at rest dropped
from a very tall building. Include columns for time, velocity, and total
distance


Time of Fall Velocity Aquired
(seconds) (meters/seconds
_______________________________________
0--------------------- 0
0.5-------------------4.9
1--------------------- 9.8
1.5-------------------14.7
2 ------------------- 19.6
2.5------------------24.5
3 -------------------- 29.4
3.5-------------------34.3
4--------------------- 39.2
4.5-------------------44.1
5--------------------- 49

total = d=49m

 

[Doc Al]

Originally posted by celect
total = d=49m

No. What you've done is give a table with columns for time and speed, not distance. I think you need a table with three columns: time, speed, and distance.

$$V=at$$

$$D=\frac{1}{2}at^2$$

 

[Student10]

I'm hoping someone can help me.

I'm working on this same Velocity table and need to understand a couple things. Is velocity the same as the speed... it should be should it? also, I'm looking for distance and while I have these equations I'm not sure what to do? Physics online is a little more difficult then I realized. But I feel if I get thru the initial reminders of calculus, I'll be just fine.

If someone could do an example even unrelated... it would be sooo helpful. thank you

Using the formulas V=aT & D=1/2aT2

..........V=aT...D=1/2aT2
T2=Time...a or g = Speed m/s... V=Velocity...Distance
0......0......0......0
.5.....4.9.......2.45
1......9.8.......9.8
1.5......14.7......22.05
2......19.6......39.2
2.5......24.5......61.25
3......29.4......88.2
3.5......34.3......120.05
4......39.2......156.8
4.5......44.1......198.45
5......49......245


Is this right so far?
Michelle