What is the negation of the statement

  • Thread starter Thread starter yxgao
  • Start date Start date
Click For Summary
SUMMARY

The negation of the statement "For each s in R, there exists an r in R such that if f(r) > 0, then g(s) > 0" is "There exists an s in R such that for each r in R, f(r) > 0 and g(s) < 0." To find the negation of any logical statement, one must apply the laws of negation in Boolean logic, including the transformations of universal and existential quantifiers, as well as the logical operators. Key laws include the negation of universal quantifiers, existential quantifiers, conjunctions, disjunctions, implications, and double negations.

PREREQUISITES
  • Understanding of Boolean logic principles
  • Familiarity with logical quantifiers: universal (∀) and existential (∃)
  • Knowledge of logical operators: conjunction (∧), disjunction (∨), implication (→), and negation (¬)
  • Ability to manipulate logical statements into standard categorical form
NEXT STEPS
  • Study the laws of negation in Boolean logic
  • Practice converting statements into standard categorical form
  • Explore examples of negating complex logical statements
  • Learn about logical equivalences and their applications in proofs
USEFUL FOR

Students of mathematics, logic enthusiasts, and anyone interested in formal reasoning and logical proofs will benefit from this discussion.

yxgao
Messages
122
Reaction score
0
What is the negation of the statement "For each s in R, there exists an r in R such that if f(r) >0, then g(s) >0."

The answer is "There exists an s in R such that for each r in R, f(r) >0 and g(s) <0."

What is the general method to find the negation of any logical statement?

Thanks!
 
Physics news on Phys.org
Originally posted by yxgao
What is the general method to find the negation of any logical statement?
While I can't give you a general method, you may find it useful to review the concept of contradictory statements from Boolean logic:

All S is P is contradictory to Some S is not P

No S is P is contradictory to Some S is P

A statement and its contradictory cannot both be true (or both be false). Thus if "All S is P" is not true, then "Some S is not P" must be true. Of course, this only applies to statements that can be put in standard categorical form.
 
Basically, you just want to distribute the negation. Use the laws

[tex]\neg \forall x: P(x) = \exists x: \neg P(x)[/tex]
[tex]\neg \exists x: P(x) = \forall x: \neg P(x)[/tex]
[tex]\neg(x \wedge y) = \neg x \vee \neg y[/tex]
[tex]\neg(x \vee y) = \neg x \wedge \neg y[/tex]
[tex]\neg(x \Rightarrow y) = x \wedge \neg y[/tex]
[tex]\neg(\neg x) = x[/tex]
 
Last edited:

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
2
Views
1K
  • · Replies 22 ·
Replies
22
Views
2K
Replies
1
Views
1K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K