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Separable DE

by Jeann25
Tags: separable
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Jeann25
#1
Mar12-06, 02:17 PM
P: 30
How would I start this one? I tried dividing by y, but that does not work

y'=xy/(1+x)
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arildno
#2
Mar12-06, 02:19 PM
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Why doesn't that work?
d_leet
#3
Mar12-06, 02:58 PM
P: 1,075
Quote Quote by Jeann25
How would I start this one? I tried dividing by y, but that does not work

y'=xy/(1+x)
Yeah why does dividing by y not work?

Jeann25
#4
Mar12-06, 03:41 PM
P: 30
Separable DE

Here's what I did:

1/y y' = x/(1+x)
ln y = 1/2 ln (1+x)+c
y = ce^(1/2 ln(1+x))

Answer's supposed to be: c*sqrt(1+x)
d_leet
#5
Mar12-06, 03:42 PM
P: 1,075
Quote Quote by Jeann25
Here's what I did:

1/y y' = x/(1+x)
ln y = 1/2 ln (1+x)+c
y = ce^(1/2 ln(1+x))

Answer's supposed to be: c*sqrt(1+x)
Yeah, ok and how is that different from what you had? Just simplify your expression with the properties of logs.
Jeann25
#6
Mar12-06, 03:56 PM
P: 30
Nevermind. I get it now. Thank you :)


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