Help calculating rotational inertia

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Homework Help Overview

The original poster seeks assistance in calculating the rotational inertia of different wheel and tire packages for a car. They provide specific details about two sets of wheels and tires, including their weights and sizes, and express uncertainty about how to begin the calculations.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relevant equations for calculating rotational inertia, specifically for disks and rings. The original poster attempts to apply the formula for rotational inertia and presents their calculations for both the 14" and 15" wheel and tire combinations.

Discussion Status

Some participants provide feedback on the calculations presented, confirming the formula used for rotational inertia. There is an ongoing exploration of the calculations and the units involved, with participants questioning the correctness of the original poster's results.

Contextual Notes

The discussion includes a focus on the application of imperial units for the calculations, and there is a recognition of the need to clarify the units of measurement for moment of inertia.

abawp
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I need to compare a wheel and tire package on my car and I need help calculating for rotational inertia. I am comparing the weights and size of two different wheels and tires, and so far, this is what I have gathered:

14" wheel & tire (tire is a 195-60-R146):
Overal Diameter - 23.2126"
Wheel weight - 17 lbs
tire weight - 21 lbs

15" wheel & tire (tire is a 195-45-R15):
Overal Diameter - 21.9094"
Wheel weight - 17.5 lbs
tire weight - 16 lbs

Now, where do I begin?
 
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Start by looking at some rotational inertia equations for disks/rings. What are they?
 
Don't think this is correct, but this is what I have come up with.

formula for rotational inertia for a disk:

I = 1/2 M * R^2, where M = mass, and R = radius?

14" wheel:

I = 1/2 * 17lbs * 7"^2
I = 416.5 in^2 lbs (not sure what the units are)

195-60-R14 tire:

I = 1/2 * 21 * 11.6063^2
I = 1,414.4172

14" wheel w/ tire:

I = 1/2 * 38 * 11.6063^2
I = 2,559.4178

Now the 15" wheel:

I = 1/2 * 17.5 * 7.5^2
I = 492.1875

195-45-R15 tire:
I = 1/2 * 16 * 10.9647^2
I = 960.0436

15" wheel w/ tire:
I = 1/2 * 33.5 * 10.9547^2
I = 2010.0921

Did I do this correct?
 
abawp said:
Don't think this is correct, but this is what I have come up with.

formula for rotational inertia for a disk:

I = 1/2 M * R^2, where M = mass, and R = radius?

That's right.

abawp said:
I = 416.5 in^2 lbs (not sure what the units are)

Your units are also correct. The SI units for moment of inertia are kg.m2, but as you are using imperial units (pounds, inches), your units are fine.

~H
 

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