
#1
Mar3006, 06:28 PM

P: 5

Why can't a static magnetic field (not changing in time) ever do work? How do I express this formulaically? My only guess is that work is zero for a closed path.




#2
Mar3006, 06:36 PM

Sci Advisor
HW Helper
P: 1,322

The force on a charged particle in a magnetic field is [tex] \vec{F} = q \vec{v} \times \vec{B} [/tex], right? Stare at that formula for a bit. Now ask yourself, how is the force related to the velocity? Then ask, how is work related to force?




#3
Mar3006, 07:07 PM

P: 5

I see, then dv/dt is 0 when the B field is static, so if a=0 then F=0 then W=0. Sound right?
Unfortunately this was on our last exam, and my answer was that W=qV and induced voltage is only a result of B flux changing in time. 



#4
Mar3006, 07:16 PM

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P: 1,322

Static Magnetic Field and Work
Wait, how did you conclude that [tex] \frac{d\vec{v}}{dt} = 0 [/tex]? The acceleration certainly isn't zero, there is a force acting.




#5
Mar3006, 07:37 PM

P: 5

Is it that the force is perpendicular to the magnetic field and work must be parallel to the displacement?




#6
Mar3006, 07:47 PM

Sci Advisor
HW Helper
P: 1,322

You are so close! The force is perpendicular to the field, but that's not what matters. What else is the force perpendicular to?




#7
Mar3006, 07:54 PM

P: 5

Ah, so because the force is perpendicular to the velocity, the force is perpendicular to the displacement.



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