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clockwise direction |
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| Apr19-06, 05:42 PM | #1 |
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clockwise direction
Find the matrix A of the linear transformation T from [tex]R^2[/tex] to [tex]R^2[/tex] that rotates any vector through an angle of [tex]135^o[/tex] in the clockwise direction.
my book does not talk about how to answer this question. I've seen a change in 90 degrees, but I dont know how to do a 135 degree. |
| Apr19-06, 06:34 PM | #2 |
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Look at the idea how to do it 90 degrees, the same idea applies.
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| Apr19-06, 10:18 PM | #3 |
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I guessed on how to get the 90 degree one, since it was mulitple choice. so i dont actually know the process, could someone explain it to me?
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| Apr19-06, 10:43 PM | #4 |
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clockwise direction
You can look at what the transformation does to the standard basis, what is T(1,0) and T(0,1)? These determine the 1st and 2nd columns of A respectively and can be found using a little trig. More generally you can find a rotation by any angle this way.
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| Apr19-06, 11:21 PM | #5 |
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how can this be found with trig? i dont even know how linear transformations have to do with rotations, not sure at all what is going on because this hw questions came out of the blue
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| Apr19-06, 11:59 PM | #6 |
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I mean you can find T(1,0) and T(0,1) in terms of sin's and cos's of your angle. Can you find T(1,0) and T(0,1)? Drawing a picture will help.
A rotation about the origin is a linear transformation. |
| Apr20-06, 12:50 AM | #7 |
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so T(1,0) represents sin(90) and T(0,1) = cos(90)?
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| Apr20-06, 09:18 AM | #8 |
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| Apr20-06, 09:48 AM | #9 |
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it's in the thrid quadrant. it makes a 45 degree angle with the x axis. so the x is [tex]-\frac{\sqrt{2}}{2}[/tex] which would be the same for the y
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| Apr20-06, 10:06 AM | #10 |
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Right, so that's the first column of the matrix for T. The second column is T(0,1), which you can find the same way.
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