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Apr19-06, 05:42 PM   #1
 

clockwise direction


Find the matrix A of the linear transformation T from [tex]R^2[/tex] to [tex]R^2[/tex] that rotates any vector through an angle of [tex]135^o[/tex] in the clockwise direction.

my book does not talk about how to answer this question. I've seen a change in 90 degrees, but I dont know how to do a 135 degree.
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Apr19-06, 06:34 PM   #2
 
Look at the idea how to do it 90 degrees, the same idea applies.
Apr19-06, 10:18 PM   #3
 
I guessed on how to get the 90 degree one, since it was mulitple choice. so i dont actually know the process, could someone explain it to me?
Apr19-06, 10:43 PM   #4
 
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clockwise direction


You can look at what the transformation does to the standard basis, what is T(1,0) and T(0,1)? These determine the 1st and 2nd columns of A respectively and can be found using a little trig. More generally you can find a rotation by any angle this way.
Apr19-06, 11:21 PM   #5
 
how can this be found with trig? i dont even know how linear transformations have to do with rotations, not sure at all what is going on because this hw questions came out of the blue
Apr19-06, 11:59 PM   #6
 
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I mean you can find T(1,0) and T(0,1) in terms of sin's and cos's of your angle. Can you find T(1,0) and T(0,1)? Drawing a picture will help.

A rotation about the origin is a linear transformation.
Apr20-06, 12:50 AM   #7
 
so T(1,0) represents sin(90) and T(0,1) = cos(90)?
Apr20-06, 09:18 AM   #8
 
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Quote by UrbanXrisis
so T(1,0) represents sin(90) and T(0,1) = cos(90)?
No, T(1,0) is a vector. Did you draw a picture? Start with the vector (1,0). Rotate it 135 degrees clockwise. What quadrant is it in? What angle does it make with the x-axis? What are it's new coordinates?
Apr20-06, 09:48 AM   #9
 
it's in the thrid quadrant. it makes a 45 degree angle with the x axis. so the x is [tex]-\frac{\sqrt{2}}{2}[/tex] which would be the same for the y
Apr20-06, 10:06 AM   #10
 
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Right, so that's the first column of the matrix for T. The second column is T(0,1), which you can find the same way.
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