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Domain of x^26x+9 / x^2 
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#1
Apr2906, 11:56 PM

P: 24

Here is the problem again
x^26x+9 / x^2 I think the answer is "all real numbers", but I don't know. I'm not used to seeing only x^2. Most of the ones I have done are x^2  4 or something like that. 


#2
Apr3006, 12:12 AM

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P: 2,952

The question as it is written makes little sense. The domain has to be defined in the first place for a function to mean anything. So the domain can be a subset of the reals, or complex numbers, or even integers. Given a particular domain, it is a perfectly valid question to determine the range of the function.
But there is one real value for x where the function ceases to be welldefined, and I think the question is asking you to find this. What happens when x = 0 ? 


#3
Apr3006, 10:33 AM

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As Curious3141 said, strictly speaking, the domain has to be "given" along with the formula describing a function. A lot of the time, however, it is understood that the domain is "all values of x for which the formula gives a valid result". One of the first things you should have learned about "domain" is "you can't divide by 0". Thus Curious3141's question "what happens when x= 0?"



#4
Apr3006, 03:56 PM

P: 24

Domain of x^26x+9 / x^2
Undefined!



#5
Apr3006, 06:07 PM

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P: 39,565

And therefore, the domain of (x^26x+9 )/ x^2 is?



#6
Apr3006, 06:18 PM

P: 25

Any value of x for which you can evaluate the term.



#7
Apr3006, 07:06 PM

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P: 2,952

A nice way of representing the domain is R\{0} which means all the reals except zero. Another way is to state the domain is [tex](\infty,0) \cup (0,\infty)[/tex] because the open interval excludes the point at zero.
If you're working in a system other than the reals, amend accordingly. 


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