Calculating Tension and Acceleration in a Rotating System

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SUMMARY

The discussion focuses on calculating the tension and acceleration of an object in a rotating system involving a wheel with a moment of inertia (I) and radius (R). The key equations derived include Newton's second law applied to both the mass and the wheel, leading to the relationship between tension (T) and acceleration (a). The final formulas established are a = mg/(I + mR²) for acceleration and T = mR²g/(I + mR²) for tension. These equations are essential for understanding dynamics in rotational motion.

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  • Understanding of Newton's second law
  • Familiarity with rotational dynamics and torque
  • Knowledge of moment of inertia (I) and its calculation
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An object of mass m is tied to a light string wound around a wheel that has a moment of inertia I and radius R. The wheel bearing is frictionless and the string does not slip. find the tension and the acceleration of the object.

I think mg-T=ma


and that I=MR^2

thats all i know can someone help me please

thank you
 
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You need to apply Newton's 2nd law to each body: the mass and the wheel.
Originally posted by bard
I think mg-T=ma
Right. That's Newton's 2nd law applied to the mass.

Now apply it to the wheel, using the rotational form: Torque = I*α (you tell me the torque).

To relate the two equations, note that a = R*α.
 
Hi Doc Al,

Almost solved it
the a i use here will be angular acceleration

so

net torque=T*R or

Ia=T*R

Ia=(mg-mRa)R

Ia=mgr-mR^2a

Ia+mgR^2a=mgr
a(Ia+mR^2)=mgr

a=mgr/I+mR^2

for acceleration the tension is a=mR^2g/(I+mr^2)
 

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