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Curved Mirrors (concave) |
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| May14-06, 07:14 AM | #1 |
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Curved Mirrors (concave)
how can you tell when the image will become real or virtual in a concave mirror, the distance?..i'm not sure
thanks in advance *edit* oh i think i know..is it the magnification, if the magnification is more than 1 then that means its virtual since it would be upright and a bigger image is that right? |
| May14-06, 07:53 AM | #2 |
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This is correct;
[tex]\frac{1}{d_{O}} + \frac{1}{d_{i}} = \frac{1}{f}[/tex] When [itex]d_{i}[/itex] is positive, the image is real; if it is negative the image is virtual. [itex]d_{i}[/itex] is the horizontal displacement of the image from the centre of the mirror. [itex]d_{O}[/itex] is the horizontal displacement of the object from the centre of the mirror and [itex]f[/itex] is the focal length of the mirror (which is positive for a concave mirror). It is possible it have a real image that is larger than the object. What is the definition of a real and virtual image? More information is available here; http://hyperphysics.phy-astr.gsu.edu...mirray.html#c3 |
| May14-06, 08:14 AM | #3 |
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Actually if the magnification is +ve , the image is virtual.
-ve->real (As per new Cartesian sign convention) |
| May14-06, 08:16 AM | #4 |
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Curved Mirrors (concave)~H |
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