## need help understanding the transistor circuit of an Boolean "NOT gate"

can some one plz link or upload a scheme or would this one i attached work? and how do you display in which direction the current flows? thats what i'm trying to show with the battery halves...
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 Mentor No, what you have drawn will not work as an inverter. Just look at the simplified schematic of some inverter gates in their datasheets: 74S04 -- http://rocky.digikey.com/scripts/Pro...296&M=SN74S04N 74HCU04 (unbuffered inverter) -- http://rocky.digikey.com/scripts/Pro...6&M=SN74HCU04N
 What I believe is: you want to let the transistor act like an inverter. The circuit you attached won't work because: 1 - you must put a resistor Rb on the base of the transistor. 2 - when the input is logic 0, the transistor is turned ON and it will behaves like a wire, therefore , a short is gonna happen because the ON state transistor will short the 6V to ground. I attached a circuit that will work properly... and here you are: As you can see, there are 2 resistors in this circuit: Rc and Rb... Rc is put so there will be no short circuit when the transistor is ON. Rb is put to limit the base current ib. This circuit will work properly as a Boolean "NOT Gate" The logic 1 input signal will turn the transistor ON, so it will act like a wire, and the output is shorted to the ground, which means the output is logic 0. And vice versa, when the input signal is logic 0, the transistor turns OFF, and there will be no current passing through the resistor, therefore the whole +Vs voltage will drop between the collector and the ground as output voltage, so the output voltage is logic 1 now ! As a summary, when the input signal is logic 1 , the output signal is logic 0...but when the input voltage is logic 0 , the output voltage is logic 1...so the circuit is acting just like a "NOT GATE" ! I hope this helps...