How Can I Calculate Deceleration and Depth for an Object Falling into Water?

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SUMMARY

This discussion focuses on calculating the deceleration and depth of an object falling into water, utilizing the initial velocity (Vo) and the final velocity (Vt) of zero. The correct approach involves using the force of water resistance, calculated with the equation F = 1/2 * ρ * A * Cd * v^2, where ρ is the water density, A is the object's cross-sectional area, Cd is the drag coefficient, and v is the velocity. The deceleration can be determined using a = F/m, and the depth can be calculated with d = 1/2 * a * t^2, where t is the time taken to stop.

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lalapsambel
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Here's my problem:
I have to find how much deceleration & how deep it will be when something fall into the water, but I just have the Vo when it strikes the water and of course Vt which is 0. I don't know how can I measure its deceleration underwater. OK, actually I just want to know how much force that the water gives when this thing strikes the water. So, I want to combine the equation F.t= m(Vt-Vo). Can I use that? But I have to get either the time and I'll use Vt=0, or the Vt and I'll use the time = 0.01 s, so it's just instanteous velocity.

What equation should I use? Please help me, it's a part of my project and if I can't solve this problem, it mean I should change the whole project!
 
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For any constant acceleration, you can treat "average" as (v0+v1)/2 - i.e. the average of the initial and final speeds. Here, v1= 0 so the average velocity is v0/2.

Decelerating at constant acceleration, -a, v(t)= v0- at so v(t)= 0 when v0- at= 0 or t= v0/a. The distance the object falls in that time is (v0/2)(v0/a)= v02/2a.

If you know the initial velocity v0 and depth d, then
d= v02/2a so a= v02/2d.
 


Hi there,

I understand your frustration with this water resistance problem. It can be challenging to calculate the deceleration and depth of an object falling into water without all the necessary information. However, there are a few things you can consider to help you solve this problem.

First, it's important to note that the equation you mentioned, F.t= m(Vt-Vo), is not the correct one to use in this situation. This equation is used to calculate the impulse, or change in momentum, of an object. It does not take into account the force of water resistance.

To calculate the force of water resistance, you can use the equation F = 1/2 * ρ * A * Cd * v^2, where ρ is the density of water, A is the cross-sectional area of the object, Cd is the drag coefficient, and v is the velocity of the object. This equation will give you the force of water resistance acting on the object at a particular velocity.

To find the deceleration of the object, you can use the equation a = F/m, where F is the force of water resistance and m is the mass of the object. This will give you the deceleration of the object as it falls into the water.

As for determining the depth of the object, you can use the equation d = 1/2 * a * t^2, where d is the depth, a is the deceleration calculated in the previous step, and t is the time it takes for the object to come to a complete stop (which can be estimated based on the initial velocity and the force of water resistance).

I hope this helps you with your problem. Remember to double-check your equations and units to ensure accuracy. Good luck with your project!
 

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