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help : greatest common factor |
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| May30-06, 04:23 AM | #1 |
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help : greatest common factor
For any n,m are intergers, d_n and d_m are divisors of n and m,
respectively. If gcd(n,m)=1, gcd(i,n)=d_n , gcd(j,m)=d_m sm=1(mod n) , tn=1(mod m), z=smi+tnj (mod nm) then gcd(z,nm)=d_nd_m. I want to know the result is true or false, and how to prove it. Thanks.
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| May30-06, 08:46 PM | #2 |
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