
#1
Jun1606, 01:03 PM

P: 140

In the context of properties of conductor & 1st Uniqueness theorem, Griffiths proves that field inside a cavity( empty of charge) within a conductor is 0.
Is the result same if we place a +q & a q (so that Q(enc)=0) suspended in air inside the cavity? 



#2
Jun1606, 01:25 PM

HW Helper
PF Gold
P: 1,198

I would say no, because Laplace's equation won't be satisfied everywhere, because of the point charges. So you can't apply the first uniqueness theorem.




#3
Jun1606, 07:22 PM

P: 140

I agree with you about the result but cannot be satisfied with your argument.As Poisson's eqn. takes into consideration Rho(r)...& still satisfies Uniqueness theorems. Lastly I think it is solved:we will have a unique V(r) function from which E follows.This V(r) will not satisfy properties of Laplace eqn.In boundary, V(r)=V(0),Following properties of a conductor...Otherwise the system I'm talking of will not exist at all.It will collapse immediately after we place them together within the cavity,following Earnshaw's theorem.Any conceptual mistake?Please help!



Register to reply 
Related Discussions  
why is electric field inside a conductor zero?  Advanced Physics Homework  42  
help with this : the field inside a conductor is zero therefore  Introductory Physics Homework  1  
Field inside Conductor  Classical Physics  20  
Electric Field inside a conductor  Introductory Physics Homework  1  
If ia charge is placed inside a conductor, is the electric field inside zero?  Introductory Physics Homework  1 