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Equiv. Class Problem 
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#1
Jul1006, 07:59 PM

P: 2

In Q[t], define the equivalence relation ~ as f(t) ~ g(t) precisely when f(t)  g(t) is a multiple of t^2  5. We define the addition and multiplication of equivalence classes as [f(t)] + [g(t)] = [f(t) + g(t)] and [f(t)] * [g(t)] = [f(t) * g(t)]
(Assume: ~ is an equivalence relation, Addition/Mutliplication of equivalence classes is welldefined, and every equivalence class contains exactly one element of the form a + bt, where a, b in Q) a) Find a, b in Q such that [3t^3  5t^2 + 8t  9] = [a + bt] b) Find a, b in Q such that [2t + 7] * [7t + 11] = [a + bt] c) Find two equivalence classes whose square is equal to [5] d) Find a, b in Q such that [a + bt]^2 + [2][a + bt] = [19] (Two possible answers) e) Find a, b in Q such that [2  t] * [a + bt] = [1] f) Which equivalence classes are zero divisors? g) Which equivalence classes have multiplicative inverses? h) How many equivalence classes are there whose square is equal to [6] ? Note: * means multiplication Now, I think I found the following solutions. Can someone verifty these and help solve the remaining parts? a) [35t  54] b) [71t + 147] c) ?? d) ?? e) ?? f) [0] = [t^2  5] (are these the only zero divisor classes??) g) ?? h) ?? 


#2
Jul1006, 09:24 PM

HW Helper
P: 2,567

What does [t] behave like? This should give you a better feel for this field (whose elements are the equivalence classes).



#3
Jul1006, 09:52 PM

P: 2

I'm lost with this problem and I have a handful of these to do. If I had an example of how to solve one of these I'm confident I can figure out the rest (I learn by example and since there aren't any with the materials I have (not even any odd solutions in the back!) I'm really desparate). Please, is there any way you could post the solutions to this one with some intermediate explanations.



#4
Jul1006, 10:58 PM

HW Helper
P: 2,567

Equiv. Class Problem
If you think about what I said for a few minutes, you'll get all the answers very easily, along with a deeper understanding. No one is going to do the problems for you, and you should be grateful for that.



#5
Jul1106, 04:07 AM

Sci Advisor
HW Helper
P: 9,396

How did you get the answers to the parts you have done? If you explain that then we'll have a better idea of what you understand.



#6
Jul1106, 11:50 AM

HW Helper
P: 2,567

Maybe I should have been more clear. [t^25]=[t]^2[5]=[0], so in a sense, [t] behaves just like sqrt(5). See how far you can push this analogy.



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