
#1
Sep106, 04:09 PM

P: 157

My problem is this,
Find the electrix flux through the top side of a cube. The cube's corner is on the origin, and is 'a' units on length. The charge 'q' is located at the origin, with the corner of the cube. I am thinking I need a double integral. One to swipe the box in the y direction (theta), and one to swipe in the x direction (phi). So, I know the component of the electric field perpendicular to the surface is (k*q*cos(theta))/(a*cos*theta)^2 . So I think I need to integrate this from 0 to (pi/4), then integrate again. But how to set up the second integral is where I am confused... Or maybe Im off track all together! Thx for any help 



#2
Sep106, 05:00 PM

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#3
Sep106, 05:14 PM

P: 157

Thx for the reply.
Im sorry, I mis stated my problem I will edit it. The cube is not centered on the origin, its corner is at the origin with the charge. So the flux through one side will not necessarly be 1/6th of the flux. 



#4
Sep106, 05:29 PM

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Find Electric Flux through cube's side, point charge on cornerIt would be quite a pain to do with an integral 



#5
Sep106, 07:50 PM

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#6
Sep106, 10:01 PM

P: 157

I see the solution perfectaly now. Thank you all, you answered my question well.
I did infact get the double integral too, wow what a mess. But getting the double integral was satisfying. 



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Jun1810, 11:22 AM

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Jun1810, 11:26 AM

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Feb412, 05:49 PM

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Feb412, 06:42 PM

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