
#1
Sep606, 03:34 PM

P: 44

Question:
An object is moving on land at a speed of 1020 km/h. This object goes from full speed to a complete stop in 1.4 seconds. In g units, what acceleration did the object 'experience' while stopping? My guess is I have to plug in 9.8 m/s into this equation, but I'm not sure how. Any help? I hope this is the right forum. Thanks 



#2
Sep606, 03:36 PM

P: 398

1 g = 9.82m/s^{2}
Do you know the formula for acceleration? 



#3
Sep606, 03:37 PM

P: 44

Thanks for the quick reply. I don't know the formula for acceleration, at least not off the top of my head.




#4
Sep606, 05:03 PM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,904

acceleration in g units
acceleration is rate of change of speed. The speed went from 1020 km/hr to 0 km/hr, a change of 1020 km/hr in 1.4 seconds.
You will want to change km/hr to m/s. 



#5
Sep606, 07:13 PM

P: 44

So it accelerated at 283.3 m/s, now do I divide that by the 9.8 m/s, and that's my answer? I came up with 28.91 g units.




#6
Sep706, 11:49 AM

P: 44

Something just accrued to me. What do I do with the 1.4 seconds? Do I take the 28.91 g units and figure out what the answer would be for 1 second, making it 20.65 g units?




#7
Sep108, 11:54 AM

P: 2

Yo so is it 28.91 or 20.65..
so what hall are you in...physics 211!!! 


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