A teacher is sitting at a park and counts all the kids and all the dogs. She comes to a total of 40 head and 100 legs. How many kids and dogs are there?

There is more than one answer. the first one is 30 kids and 10 dogs.

There is no trick animal (ie: a three legged dog or two headed kid.).

---------

Can anyone figure this out??? I can't. please let me know the answer.
 PhysOrg.com science news on PhysOrg.com >> Galaxies fed by funnels of fuel>> The better to see you with: Scientists build record-setting metamaterial flat lens>> Google eyes emerging markets networks
 This just leads to two equasions and two unknowns. So mathematically speaking there is one unique solution. Please let us know if you find otherwise.
 Recognitions: Homework Help Science Advisor Are there any goats?

mathematically speaking , another answer is not possible , may be some trick is involved
 I will.. I know there is some kind of trick to it... its racking my brain trying to think of it!
 2k+4d=100 k+d=40 One answer. This must be a trick question then. Let's see, no trick animals allowed, so it must be a trick to how or what she's counting.
 Blog Entries: 1 Recognitions: Gold Member My solution: 40 kids, 10 of which are puppies EOM

 Quote by GraphicSpaz A teacher is sitting at a park and counts all the kids and all the dogs. She comes to a total of 40 head and 100 legs. How many kids and dogs are there? There is more than one answer. the first one is 30 kids and 10 dogs. Find ONE more answer! There is no trick animal (ie: a three legged dog or two headed kid.). --------- Can anyone figure this out??? I can't. please let me know the answer.
Is this the problem EXACTLY as given to you?

 Quote by GraphicSpaz A teacher is sitting at a park and counts all the kids and all the dogs. She comes to a total of 40 head and 100 legs. How many kids and dogs are there?
The answer is indeed a trick, assuming that:
1) All "kids" she counts have 2 legs and 1 head
2) All "dogs" she counts have 4 legs and 1 head
3) She is not including anything else in her count (IE, only the legs and heads of kids and dogs in the park, and not, say, her own legs and head)
4) Her count is accurate
5) "Kids" and "dogs" are constant throughout the problem
6) Numbers provided are in base 10

The question is also poorly worded. She is not, in fact, counting "all the kids and all the dogs". She is actually counting all the kids' legs, kids' heads, dogs' legs, and dogs' heads. The fact that she counts "40 head" is assumably just a typo (should be "40 heads", but that's easily forgiveable), and if you're REALLY being persnickity, it should specify that the teacher counts all the heads and legs "in the park", and should ask how many kids and dogs are "in the park", rather than just how many there are.

My guess is the answer they're looking for is 29 kids and 10 dogs, but she counts her *own* legs and head.

DaveE
 maybe dogs mean ugly kids?

 Quote by davee123 The fact that she counts "40 head" is assumably just a typo
I wondered about this too. I tested a scenario based on the premise there were 40 'head of cattle' in the park, but I didn't get sensible results.
 What's red and has got two legs?
 You know, nowhere does it say she counted ONLY kids and dogs. Maybe there was a table. Or better yet, something common in a park (that is not an animal) but has both a head and a number of legs...
 I suppose we could be overlooking the obvious: There are 10 dogs, 29 kids, 1 teacher. 40 heads, 100 legs.

 Quote by J77 What's red and has got two legs?
Half a dog!

 Quote by J77 Half a dog!
Lol. Its funnier the way I first heard it.

What has two legs and bleeds?