How to Calculate the Distance of a Trip with a Rest Stop and Constant Speed?

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Discussion Overview

The discussion revolves around calculating the distance of a trip where a person drives at a constant speed with a rest stop included. Participants explore the relationship between average speed, distance, and time, applying mathematical reasoning to derive the distance traveled.

Discussion Character

  • Mathematical reasoning
  • Homework-related
  • Technical explanation

Main Points Raised

  • One participant presents an initial calculation, suggesting the trip distance is 191.43 km based on their derived time of 2.70 hours.
  • Another participant proposes a different approach, concluding the trip distance is 121 km and the time taken is 1.71 hours, using equations based on average speed and time in motion.
  • A participant expresses confusion about mathematical notation, specifically the division symbol, indicating a lack of familiarity with the math involved.
  • Further clarification is provided on the calculations, detailing the steps taken to arrive at the distance and time, with a focus on the average speed formula.
  • There is a question about the derivation of "18.8t" from the equations, leading to an explanation of how that term was obtained through algebraic manipulation.

Areas of Agreement / Disagreement

Participants present differing calculations for the trip distance, with one suggesting 191.43 km and another asserting it is 121 km. The discussion reflects multiple competing views without a consensus on the correct answer.

Contextual Notes

There are unresolved aspects regarding the assumptions made in the calculations, particularly concerning the interpretation of average speed and the effects of the rest stop on total travel time.

Embison
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The question is:

A person takes a trip, driving with a constant speed 89.7 km/h except for a 21.5 min rest stop.
If the person's average speed is 70.9 km/h, how far is the trip? Answer in units of km.



I haven't done this kind of thing for years! and I was just wondering if I solved it properly.. here is what i came up with...



time = 89.7 x (t - 21.5/60) = 70.9, 89.7 t - 38.5 = 70.9 t, t = 2.70 h

distance = 70.9 x 2.70 = 191.43 km


Is that right? Any help would be greatly appreciated.

Thanks
 
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Let d be the length of the trip (km). Let t be the time of the trip (hours).

<br /> 70.9t = d<br />
<br /> 89.7(t - 21.5/60) = d<br />
<br /> 70.9t = 89.7t - 1928.55/60<br />
<br /> 18.8t = 1928.55/60<br />
<br /> t = 1.71<br />
<br /> d = 70.9t = 121<br />

The trip was 121 km long and took 1.71 hours.
 
i wish i knew how you did that...

but i don't even know what / <-- means?

i think it means to divide but I've forgotten all of the math i was taught.

it's been years.
 
Okay, here's a "translation".

As Tron3k said "Let d be the length of the trip (km). Let t be the time of the trip (hours)."

Since the person stopped for 21.5 min.= 21.5 min/60 min/h (21.5 divided by 60)= 0.358 h, the time actually in motion (at a constant speed of 89.7 km/h) was t- 0.358 hours. Since speed is defined as "distance divided by time" we have 89.7= d/(t-0.358) or (multiply by t-0.358 to get rid of the fraction) 89.7(t-0.358)= d.

We are told that the average speed (averaging the constant 89.7 when he was moving with the 0 speed while stopped) was 70.9 km/h.
The average speed is calculated (again using "distance divided by time") using the total time: 70.9= d/t or d= 70.9t.

Since d is the same in both equations, d= 70.9t= 89.7(t- 0.358)=
89.7t- (89.7)(0.358)= 89.7t- 32.15 or
70.9t= 89.7t- 32.15

Subtract 89.7t from both sides: -18.8t= -32.15. Now divide both sides of the equation by -18.8: t= -32.15/-18.8= 1.71 hours.
(Much to my amazement, the same answer Tron3k got!)

Now put that back into either d= 89.7(t- 0.358) or d= 70.9t:
Since d= 70.9t is easier: d= 70.9(1.71)= 121 km.
 
Originally posted by Embison
i wish i knew how you did that...

but i don't even know what / <-- means?

i think it means to divide but I've forgotten all of the math i was taught.

it's been years.



hahaha rofl :wink:
 
I wanted to ask how you got 18t?
 
K_go_1 said:
I wanted to ask how you got 18t?
? What "18t"? I did get "18.8t" exactly like I said:

70.9t= 89.7t- 32.15

Subtract 89.7t from both sides
70.9t- 89.7t= (70.9- 89.7)t= -(89.7- 70.9)t= -18.8t.
That made the equation -18.8t= -32.15 so I multiplied both sides by -1:

18.8t= 32.15.

How did you find this thread? It is 7 years old!
 

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