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Molecule Speed |
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| Sep27-06, 10:26 AM | #1 |
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Molecule Speed
A physics student measures molecular speeds in a laboratory apparatus and concludes that the distribution of speeds is such that:
10% have a speed of 200 m/s 10% gave a speed of 250m/s 15% have a speed of 500m/s 30% have a speed of 650m/s 20% have a speed of 900m/s 15% have a speed of 1300 m/s Calculate a) the average speed b) the rms speed c)the most probable speed Assuming that the apparatus contains and ideal gas with the molecular mass m = 50 x 10^-3 kg/mol, and the above distribution of speeds d) determine the temperature of the gas in the apparatus a) The precentages throw me off in this problem. I know that to find the average speed, I need to add up all the speeds^2 and divide by the total number of molecules. [(1 x 200m/s) + (1 x 250m/s) + (1.5 x 500 m/s)+ (3.0 x 650 m/s) + (2 x 900m/s) + (1.5 x 1300m/s)]/10 b) [(1 x 200m/s)^2 + (1 x 250m/s)^2 + (1.5 x 500 m/s)^2 + (3.0 x 650 m/s)^2 + (2 x 900m/s)^2 + (1.5 x 1300m/s)^2]/10 =1.15x 10^6 m^2/s^2 The rms speed = sqrt(1.15x 10^6 m^2/s^2) c) I really don't know what the most probable speed is or how to go about calculating it please help!! d)I know that the rms speed = sqrt(3RT/M) I'm not too good at math ( if you didn't already realize by now) so I'm not sure how to set the equation to solve for T. T^2 = sqrt((Vrms^2(M))/3RT) Any help is much appreciated. Thanks in advance. |
| Sep27-06, 10:41 AM | #2 |
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10 have a speed of 200 m/s 10 gave a speed of 250m/s 15 have a speed of 500m/s 30 have a speed of 650m/s 20 have a speed of 900m/s 15 have a speed of 1300 m/s First get rid of the square root by squareing both sides: (rms speed)2= 3RT/M. Now isolate T by multiplying both sides of the equation by M and dividing both sides by 3R: T= M(rms speed)2/3R. |
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