|Oct6-06, 04:57 PM||#1|
White light (ranging in wavelengths from 380 to 750 nm) is incident on a metal with work function Wo = 2.46 eV.
(a) What is the maximum kinetic energy of the electrons emitted from the surface?
KEmax = eV
E = hf = hc/lamda.
E = (6.626*10^-34)(3*10^8) / (750*10^-9) = 2.6504E-19
I know to get KEmax i need to do 2.35- something = 0
|Oct6-06, 05:02 PM||#2|
Note that energy of the photon is 'inversely proportional' to wavelength, and directly proportional to frequency.
The KEmax(photoelectron) = Emax(photon) - Wo
|Oct6-06, 05:09 PM||#3|
|Oct6-06, 05:18 PM||#4|
Your E_max value is the energy contained within the photon of light.
For every photon absorbed (E_max worth of energy), some amount of that energy is spent removing the electron from the metal and the rest goes into the KE of the electron.
KE_max_electron = E_max - W_o
You are given a value for W_o in terms of electronvolts (a unit of energy) and you have previously calculated the E_max value, so you should be able to calculate from here the max KE value of the electron.
1 eV = 1.602176462 E-19 Joules
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