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I have problems with integrating this... :( |
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| Oct8-06, 03:38 AM | #1 |
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I have problems with integrating this... :(
[tex]
\int_{0}^{x}\frac{1}{\sqrt{a^2 - b/x}}dx [/tex] I have tried substituting 1/x with u and so on... But it doesn't seem to work :( Thanks in advance! |
| Oct8-06, 03:56 AM | #2 |
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1/Sqrt(a^2 - b/x)
1/sqrt(a^2x - b)/Sqrt(x) Sqrt(x)/ Sqrt(a^2x - b) Let u = a^2x - b du/dx = a^2 du/a^2 = dx u+b/a^2 = x Integral becomes - (1/a)Sqrt(u+b) * 1/Sqrt(u) * du/a^2 1/a^3 + 1/a^3sqrt(b/a) du |
| Oct8-06, 06:50 AM | #3 |
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Thank you :)
(By the way, I think you meant 1/a^3[sqrt((u+b)/u)] for the last part, right?) |
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