Why Does a Skydiver's Acceleration Differ from Calculations?

  • Thread starter Thread starter holly
  • Start date Start date
  • Tags Tags
    Falling
Click For Summary
SUMMARY

The acceleration of a skydiver with a mass of 100 kg experiencing 500 N of air resistance is calculated using the formula a = F/m. The correct force acting on the skydiver is 481 N (981 N downward minus 500 N upward), resulting in an acceleration of approximately 0.49g. The professor's answer of 0.2g is incorrect, likely due to rounding or misunderstanding. Students are encouraged to clarify concepts with instructors and practice further to enhance their understanding.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Basic knowledge of free body diagrams (FBD)
  • Familiarity with gravitational force calculations
  • Ability to perform unit conversions (e.g., from Newtons to g-forces)
NEXT STEPS
  • Review Newton's Second Law of Motion in detail
  • Practice drawing and analyzing free body diagrams (FBD)
  • Learn about forces acting on objects in free fall
  • Explore the concept of terminal velocity and its implications
USEFUL FOR

Students studying physics, particularly those learning about forces and motion, as well as educators seeking to clarify concepts related to acceleration and air resistance.

holly
Messages
184
Reaction score
0
Well, you'd think I could understand these problems by now, but...

Q. A falling skydiver of mass 100 kg experiences 500-N air resistance. The acceleration of the skydiver is: a) More than .5g b).2g c).4g d).5g.

The prof gave the answer as .2g, but I get .5g by this: a=F/m. I put in 500N for F, and 1000N for his mass. Am I doing it backwards? A difficulty is that the professor will purposefully give wrong answers to us in order to "make us think," but we never know which are the wrong ones and which are right because we are just now learning this...makes it very hard for me to progress...plus I'm dumb I think.

Thanking you for any help!
 
Physics news on Phys.org
Originally posted by holly
Well, you'd think I could understand these problems by now, but...

Q. A falling skydiver of mass 100 kg experiences 500-N air resistance. The acceleration of the skydiver is: a) More than .5g b).2g c).4g d).5g.

The prof gave the answer as .2g, but I get .5g by this: a=F/m. I put in 500N for F, and 1000N for his mass.

Draw a FBD.

981N pushing down. 500N pushing up. Total of 481 pushing down.

[tex]a = \frac{F}{m}[/tex]

[tex]a = \frac{481}{100}[/tex]

a = 4.81

g = 4.81/9.81
g = 0.49

Your prof is a moron.
 


It sounds like you are on the right track with your understanding of the problem. The equation a = F/m is correct, and if you plug in the values of 500N for F and 100 kg for m, you should get an acceleration of .5g.

However, it is possible that the professor may have rounded the answer to .2g for simplicity. It is also possible that there is some other factor at play that you may not be aware of yet.

In any case, it can be frustrating when you feel like you are not understanding a concept, especially when the professor intentionally gives wrong answers. My advice would be to seek clarification from the professor or a teaching assistant and ask for more practice problems to solidify your understanding. Don't be too hard on yourself for not understanding right away - learning takes time and practice. Keep at it and you will get there!
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
11K
Replies
3
Views
4K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
1
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
4K
Replies
18
Views
3K
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
13
Views
4K