What Is the Correct Electric Field Calculation for a Point Charge?

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Homework Help Overview

The discussion revolves around calculating the electric field generated by a point charge, specifically a charge of 2 x 10^-9 C at a distance of 10 cm. Participants are exploring the correct application of the formula for electric fields in electrostatics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing the formula for electric fields, with one participant attempting to apply a formula but expressing confusion about an extra unit in their calculation. Others provide the standard formula for electric fields and clarify the distinction between electric field and electric potential.

Discussion Status

The discussion is active, with participants offering different perspectives on the calculation. Some guidance has been provided regarding the correct formula to use, and there is an acknowledgment of a potential miscalculation in the original attempt.

Contextual Notes

There appears to be some confusion regarding the application of units in the formula, as well as the distinction between electric field and electric potential. Participants are working within the constraints of a homework problem, which may limit the information available for discussion.

nautica
The electric field at a distance of 10 cm from an isolated point charge of 2 x 10^-9 C is:

A)1.8 N/C
B)180 N/C
C)18 N/C
D) 1800 N/C
E)none of these

This is the formula I used Q=rv/k

so (2x10^-9 C)(9x10^9 Nm^2) / .1 m C^2

I am getting 180 N m/C - I have an extra m in the equation, which would make it none of the about. Evidently I am doing something wrong.

Thanks
Nautica
 
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[tex]E = \frac{kq}{r^2}[/tex]
 
You want E, not V.

For a point charge:

E = kq/r^2
 
1800 N/C, thanks, nautica
 

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