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Can anyone solve this problem...? |
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| Nov3-06, 07:01 AM | #1 |
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Can anyone solve this problem...?
Hi everybody,
I'm wrestling with the following problem: Suppose a variable is normaly distributed, then is this same variable still normal distributed when raised to the power of 3? I know if the variable is raised to the power of 2 a chi-squared distribution is obtained, but what happens when raised to the power of 3? I have a feeling that the variable is still normaly distributed but I can't prove it. Let me take this question one bit further; does anyone know what kind of transformation I have to apply to obtain the standard deviation of the transformed varaible? Thank you and nice weekend Jellis |
| Nov3-06, 07:24 AM | #2 |
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The answer to your first question is, in general no. Any non-linear transformation of a normally distributed variable gives one that is not linearly distributed. I'm not sure why you would accept that the square of a normally distributed variable is not normally distributed but think that the cube would be!
How you would obtain the standard deviation of a transformed variable depends strongly on the transformation. |
| Nov3-06, 08:10 AM | #3 |
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Hi,
Thanks for the reply. Of course, If the chi-square distribution is not normal then the cubic isnt normaly distributed either. I made a excel sheet in which I made the mistake to raise the 3rd power of the frequency instead of the variable of the distribution... No wonder it still looked normally distributed I still meant the transformation of raising the 3rd power of a normal distributed variable. So let me rephrase th equestion: What kind of mathematical operation do I need to do to obtain the standard deviation of this ‘new’ variable? Hope you can link me some sort of solution on the web... Jellis |
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