## Distance under constant acceleration

A body starts from rest with an acceleration of 11m/s².

What is it's velocity after 6 seconds. (I got 66 for that) and how far did it travel?

What forumla do I have to use for this?

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 Recognitions: Homework Help There is a well-known expression which represents displacement under constant acceleration. Try to find it. (Either here or google it up.)
 Is displacement the same as distance?

Recognitions:
Homework Help

## Distance under constant acceleration

 Quote by Alpha[X]² Is displacement the same as distance?
Yes it is, in this case.

 What about the first part of the question? I tried to average out the velocity and then using the d=vt formula I got 198m.

 Quote by Alpha[X]² What about the first part of the question? I tried to average out the velocity and then using the d=vt formula I got 198m.
Yes, you did it correctly. Remember that you could calculate the displacement averaging out the velocity only because the acceleration is constant.

The other formula would be: d = (1/2)at2. Check that the solution is the same.

Try to show that v(average)*t = (1/2)at2