|Nov13-06, 11:26 AM||#1|
nR = 100 * 0.01e-3 / 300 (the expression with kPa as the units of pressure)
nR = 100e3 * 0.01e-3 / 300 (the expression with Pa as the units of pressure)
nR = (100e3 / 1.013e5) * 0.01e-3 / 300 (the expression with atm as the units of pressure)
Help, please! I'm not sure what I'm screwing up on! Thanks to anybody who can help with this...
|Nov13-06, 12:07 PM||#2|
|Nov13-06, 12:16 PM||#3|
The e-3 is the conversion factor from m^3 to liters, which is why it's included. The third is because I've had success going from Pascals to Atmospheres before with this formula, and I'm a little n00bish with using it. Lemme re-write those with units...
nR = 100 kPa * 0.01 m^3 * (1 L / 1e-3 m^3) / 300 K
nR = 100e3 Pa * 0.01 m^3 * (1 L / 1e-3 m^3) / 300 K
nR = (100e3 Pa * (1 atm / 1.013e5 pa) ) * 0.01 m^3 * (1 L / 1e-3 m^3) / 300 K
I think I just found my mistake. I feel like an idiot for that one...
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