| Thread Closed |
computation of integrals. |
Share Thread | Thread Tools |
| Nov13-06, 01:45 PM | #1 |
|
|
computation of integrals.
i need to solve/prove the next two integrals:
[tex]\int\frac{dx}{u^2+u+4}[/tex] and i need to show that: [tex]\int_{0}^{\pi}\sqrt{1+sinx}dx=4[/tex] the problem is that i have a clue to substitute u=sinx and then sin(pi)=0=sin0 so the integral should be equal zero, is it not? ofcourse the integrand becomes: sqrt(1+u)/sqrt(1-u^2) |
| Nov13-06, 01:58 PM | #2 |
|
|
For the first you can use the method of partial fractions.
You're right about the second. With the given limits, the integral is equal to zero. |
| Nov13-06, 01:59 PM | #3 |
|
|
substitute u = 1 + sin x. Are you sure the integral is equal to 4, not -4?
|
| Nov13-06, 02:05 PM | #4 |
|
|
computation of integrals.
But the plot (area) of the function sqrt(1+sin(x)) from 0 to pi seems to be non-zero!
|
| Nov13-06, 02:06 PM | #5 |
|
|
It's non-zero.
|
| Nov13-06, 02:06 PM | #6 |
|
|
neutrino, how would i use partail fractions here?
i mean i need to decompose u^2+u+4 into a product of terms, but i have complex roots here. |
| Nov13-06, 02:07 PM | #7 |
|
|
complete the square.
|
| Nov13-06, 02:11 PM | #8 |
|
|
you mean something like this: u^2+u+4=(u-2)^2+5u
i still dont get an appropiate term to integrate. |
| Nov13-06, 02:12 PM | #9 |
|
|
More like (u +0.5)^2 + 15/4
|
| Nov13-06, 02:15 PM | #10 |
|
|
ok, thanks.
btw, what about the second integral does it equal zero or it really does equal 4? |
| Nov13-06, 02:17 PM | #11 |
|
|
u^2+u+4= (u + 0.5)^2 + 15/4.
edit: too slow, the second integral should equal minus -4, I guess they're defining is it as area so you just need the modulus. |
| Nov13-06, 02:21 PM | #12 |
|
|
Not -4. I just put the function through the Integrator and substituted the values, and I got 4. This graph is completely above the x-axis.
|
| Nov13-06, 02:22 PM | #13 |
|
|
Btw, you will need to know what the derivative of the inverse tangent is.
|
| Nov13-06, 02:28 PM | #14 |
|
|
Oops, I'm missing/added a minus somewhere. Didn't have the common senese to think about the graph :).
|
| Nov15-06, 06:16 AM | #15 |
|
|
wait a minute, then integral does converge to 4, care to explain how, where did i get it wrong?
|
| Nov15-06, 06:35 AM | #16 |
|
|
For the integral try the sub
[tex] \tan\frac{x}{2}=t [/tex] Daniel. |
| Nov15-06, 06:53 AM | #17 |
|
|
but what's wrong with the substitution that im given a hint to use here?
i.e sinx=u? |
| Thread Closed |
| Thread Tools | |
Similar Threads for: computation of integrals.
|
||||
| Thread | Forum | Replies | ||
| Question about Gaussian Integrals and Path Integrals | General Physics | 2 | ||
| Finite-part integrals (Hadamard) integrals with Mathematica | Math & Science Software | 11 | ||
| Counterfactual Computation | General Physics | 3 | ||
| limit computation | Precalculus Mathematics Homework | 3 | ||
| limit computation | Calculus & Beyond Homework | 4 | ||