
#1
Nov1506, 10:24 PM

P: 4

I searched and wasn't able to find what I was looking for. I need to find the theoretical yield so I can find the percent yield, which I know how do to. I just can't remember how to find theoretical yield from a balanced equation. My equation which I believe to be correct is NaNO2+HSO3NH2=NaHSO4+H20+N2. Could you let me know what I need to do, thanks.




#2
Nov1506, 11:07 PM

P: 1,239

[tex] NaNO_{2} + HSO_{3}NH_{2} \rightarrow NaHSO_{4}+H_{2}O+N_{2} [/tex]
Find the number of moles of each starting material Determine the limiting reactant Calculate the moles of product expected if the yield was 100% based on the limiting reactant Convert moles to grams 



#3
Nov1506, 11:36 PM

P: 4

Ok I determined the moles of NaNO2 and determined that was the limiting reactant, I think. Because I was given the mass of NaNO2 to be .1120g I figured that to be .0016mol NaNO2. I'm not sure how to calculate the theoretical yield of N2 in mols. I also found mol N2 collected to be .00156 mol.




#4
Nov1506, 11:49 PM

P: 1,239

Theoretical yield
If [tex] NaNO_{2} [/tex] is the limiting reactant, than the theoretical yield of [tex] N_{2} [/tex] is 0.0016 moles.




#5
Nov1506, 11:53 PM

P: 4

I just need to find the theoretical yield of N2 in moles. I used the equation n=pv/rt to find mol N2, if that helps. We basically measured the volume of N2 gas by causing a reaction inside a test tub. When the gas was produced from the test tube the volume in the buret dropped and we moved a tube with a funnel and water down the buret to keep the pressure equal.




#6
Nov1606, 10:23 AM

P: 167

Percent yield = (Actual yield / Theoretical yield) x 100% You can calculate this using moles. 



#7
Nov1606, 12:25 PM

P: 1,116

I assume either you or a book reacted 0.1120g of NaNO_{2} and then, experimentally or because the book said so, you got a value for the amount of N_{2} created. Now, just work out the mass of N_{2} created from 0.1120g, assuming the reaction is 100% efficient. This will give you the theoretical yield. After this, take the value of N_{2} you actually got and divide it by the value you just calculated (but obviously with the same units). Then multiply by 100 to get your percentage yield. I hope that all of the explanations have put a different light on the problem and that you start to understand it in your own way I hope this helps. The Bob (2004 ©) 



#8
Nov1606, 02:00 PM

P: 4

Yes thanks, I was able to finish it this morning. I think I got the percent yield to be around 97%. So not to bad I guess. Thanks for your help. Sorry about posting in the wrong section. It just seemed like the right place to put it.



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