Solving Cube & Sphere Geometry Problem - Help Needed

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Discussion Overview

The discussion revolves around a geometry problem involving a cube and an inscribed sphere. Participants explore methods to determine the number of complete unit cubes contained within the sphere, with a focus on both conceptual understanding and mathematical reasoning.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents the problem of finding the number of complete unit cubes within a sphere inscribed in a cube, seeking guidance on how to approach it.
  • Another participant suggests simplifying the problem by first considering a 6 unit square and a 6 unit diameter circle to build intuition.
  • A later reply offers a detailed method involving symmetry and distance calculations from the sphere's center to the corners of the unit cubes, ultimately proposing that 56 unit cubes are contained within the sphere.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the solution, and there are varying levels of interest and engagement with the problem. Some participants express frustration over the lack of responses, while others find the problem less engaging.

Contextual Notes

The discussion includes assumptions about the geometry involved and the method of calculating distances, but these are not fully resolved or agreed upon by all participants.

recon
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I am having difficulty solving the following problem:

"A cube of edge 6 cm is divided into 216 unit cubes by planes parallel to the faces of the cube. A sphere of diameter 6 cm is inscribed in the large cube so that the faces of this cube are tangent to the sphere. What is the number of complete unit cubes contained in the sphere?"

Anyone care to point me in the right direction?
 
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try doing it for a 6 unit square and 6 unit diameter circle first. maybe that will help.
 
Hmmm, no replies...is the question really that hard? Or are you not helping me because you think it is homework? If that's the case, you're wrong. I'm just doing the problem out of interest.

So, please, please help me :frown: .
 
It's not hard, it's just not that interesting for me cos it's fiddly.

here's a long winded way to do it:

for each cube, pick the furthest corner from the centre of the sphere, find the length from that corner to the centre of the sphere - not too hard, and see if its less than the radius of the sphere. by symmetry you only need to do it for something like 27 cubes. and clearly none on the surface of the larger cube will work, and that's 19 of the 27 got rid of straight away. of the remaining 8, only one, the furthest from the centre needs any consideration, really, and as sqrt 12 > 3 its furthest corner lies outside the sphere,

so the answer appears to be 7*8=56


that do you?
 

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