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Help in solving a second-order linear differential equation |
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| Dec6-06, 12:08 PM | #1 |
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Help in solving a second-order linear differential equation
[tex]
\frac{{d^2 y}}{{dx^2 }} + \left( {Ax + B} \right)y = 0 [/tex] I have tried lots of substitions, but a solution won't pop out. Can anyone help solve this? Thanks. |
| Dec7-06, 09:31 AM | #2 |
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Make the change of variable
[tex]Ax + B = \lambda u [/tex] (lambda is a constant) this will give you [tex]\frac{A^2}{\lambda^2} \frac{d^2 y}{d u^2} + \lambda u y = 0 [/tex] so if you then set [tex] \lambda = -A^{\frac{2}{3}} [/tex] you then have [tex] \frac{d^2 y}{d u^2} - u y = 0 [/tex] which is the Airy equation (in u). Have a look on Wikipedia or elsewhere on Airy functions and such - or just type in "Airy Equation". edit: note you will actually get three different solutions as the condition for lambda is [tex] \frac{\lambda^3}{A^2} = -1 [/tex] which means that there are three values of lambda that satisfy this (i.e. three distinct cube-roots) - one will be real-valued (already given) plus two complex ones. Here is a link for the Airy function http://mathworld.wolfram.com/AiryFunctions.html |
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