
#1
Jan2407, 08:04 PM

P: 18

Problem.
Find Work done by each path. My Solution. ab, cd >> W=P(delta)V ac, bd >> W=0 My Question. What is the work done by the gas (path ad)? My Thoughts. There is a change in both pressure and volume. However, the equation to find the work in this situation is "W=P(delta)V". There is no (delta)P. 



#2
Jan2507, 07:38 PM

P: 20

could anyone help him?I'm kinda interested in the answer to this as well!




#3
Jan2507, 08:29 PM

P: 312

Are you familiar with integration? The answer is always found by calculating the area under the curve, which is exactly what you did for all the other ones. In this case, the area is a trapezoid




#4
Jan2507, 08:38 PM

P: 20

Work Done by Gas PV Diagram
so the work done from a to d is W = deltaP * deltaV
very good, P is no longer constant so integrate that as well as if it was that simple 


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