Work Done by Gas PV Diagram


by Malicious
Tags: diagram, work
Malicious
Malicious is offline
#1
Jan24-07, 08:04 PM
P: 18
Problem.

Find Work done by each path.

My Solution.
a-b, c-d >> W=P(delta)V
a-c, b-d >> W=0

My Question.
What is the work done by the gas (path a-d)?

My Thoughts.
There is a change in both pressure and volume. However, the equation to find the work in this situation is "W=P(delta)V". There is no (delta)P.
Phys.Org News Partner Science news on Phys.org
Internet co-creator Cerf debunks 'myth' that US runs it
Astronomical forensics uncover planetary disks in Hubble archive
Solar-powered two-seat Sunseeker airplane has progress report
JJ420
JJ420 is offline
#2
Jan25-07, 07:38 PM
P: 20
could anyone help him?I'm kinda interested in the answer to this as well!
turdferguson
turdferguson is offline
#3
Jan25-07, 08:29 PM
P: 312
Are you familiar with integration? The answer is always found by calculating the area under the curve, which is exactly what you did for all the other ones. In this case, the area is a trapezoid

JJ420
JJ420 is offline
#4
Jan25-07, 08:38 PM
P: 20

Work Done by Gas PV Diagram


so the work done from a to d is W = deltaP * deltaV
very good, P is no longer constant so integrate that as well
as if it was that simple


Register to reply

Related Discussions
8:1 Mux Pin Diagram Engineering, Comp Sci, & Technology Homework 0
Is the Loedel Diagram a Special Case of the Minkowski Spacetime Diagram? Special & General Relativity 11
N-, V- and M-diagram Engineering, Comp Sci, & Technology Homework 6
Pv=nrt and PV diagram Introductory Physics Homework 2
Difference between Block diagram, Flowsheet and Flow diagram Engineering Systems & Design 1