Towing a 25.0 kg suitcase at constant speed with handle at an angle

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Homework Help Overview

The discussion revolves around two distinct physics problems: one involving the towing of a suitcase at constant speed with a force applied at an angle, and the other concerning the dynamics of a mass rotating in a circle while attached to a string. The first problem focuses on determining the angle of force application, while the second explores the range of speeds for a rotating mass before a string breaks.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the angle at which a force is applied to a suitcase and the implications of friction in that scenario. Others introduce a separate problem involving circular motion and the tension in a string, raising questions about the conditions under which the string will break.

Discussion Status

Some participants have made attempts to solve the problems, with one suggesting a specific angle for the suitcase problem and another providing a formula for the speed of the rotating mass. However, there is a mix of responses, including reminders about the importance of personal effort in problem-solving.

Contextual Notes

There appears to be a lack of detailed information regarding the angle in the first problem and the specific conditions for the second problem, which may affect the discussions and solutions proposed.

PrudensOptimus
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A woman at an airport is towing her 25.0 kg suitcase at constant speed by pulling on a strap at an angle of above the horizontal (Fig. P5.6). She pulls on the strap with a 30.0 N force, and the friction force on the suitcase is 20.0 N


what is the angle she pulls the suitcase with
 
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wait i got it, it's 48.19 lol simple trig problem.
 
A light string can support a stationary hanging load of 24.0 kg before breaking. A 3.60 kg mass attached to the string rotates on a horizontal, frictionless table in a circle of radius 0.800 m. What range of speeds can the mass have before the string breaks?
 
lol i found the answer again...

v = sqrt(235.2*r/m)
 
Guess this means you need to put a bit more of your own effort into these problems before running for help, huh?

cookiemonster
 

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