## Design of suitable pin size

Appreciate if someone can check my answers to the following question:

A beam hinged at one end and simply supported at the other is subjected to the loading shown. A design calculation is required to determine the suitable size of hinge pin. If wrong, could you point me in the right direction.

Data Shear strength of pin material = 20 MN/m^2
Factor of safety = 5

Drawing of system can be found here:

http://img206.imageshack.us/img206/6549/oc2q3gc5.jpg

a) Use these conditions to determine the reaction forces RP and R1

b) State the maximum working shear stress in the pin.

c) Calculate a suitable diameter for the pin to the nearest millimeter.

a) My answers are RP = 1700 N, and R1 = 800 N.

c) My answer = 16 mm
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 Quote by BIGEYE Appreciate if someone can check my answers to the following question: A beam hinged at one end and simply supported at the other is subjected to the loading shown. A design calculation is required to determine the suitable size of hinge pin. If wrong, could you point me in the right direction. Data Shear strength of pin material = 20 MN/m^2 Factor of safety = 5 Drawing of system can be found here: http://img206.imageshack.us/img206/6549/oc2q3gc5.jpg a) Use these conditions to determine the reaction forces RP and R1 b) State the maximum working shear stress in the pin. c) Calculate a suitable diameter for the pin to the nearest millimeter. a) My answers are RP = 1700 N, and R1 = 800 N. b) My answer 4 MN/m^2 c) My answer = 16 mm
Your answers look correct to me. The pin is in a classic case of double shear.
 Thanks for taking the time.

## Design of suitable pin size

 Quote by PhanthomJay Your answers look correct to me. The pin is in a classic case of double shear.
hey guys .. im just wondering how you went about calculating the maximum shearing stress in the pin, and from that determining pin size ...

your help would be of most value ..

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 Quote by komy hey guys .. im just wondering how you went about calculating the maximum shearing stress in the pin, and from that determining pin size ... your help would be of most value .. Thanks in advance
The allowable shear stress in the pin with a 5.0 safety factor is "given" as 20/5 = 4MN/m^2. However, the pin is in double shear, so effectively the allowable shear stress can be taken as twice that value (8MN/m^2). The 1700N pin force was calculated from statics. Pin shear stress is shear force divided by cross sectional area of pin (1700N/A = 8MN/m^2). Solve for A, then diameter; watch units and decimal point.

Please ask again if you don't understand the concept of double shear.

 Quote by PhanthomJay The allowable shear stress in the pin with a 5.0 safety factor is "given" as 20/5 = 4MN/m^2. However, the pin is in double shear, so effectively the allowable shear stress can be taken as twice that value (8MN/m^2). The 1700N pin force was calculated from statics. Pin shear stress is shear force divided by cross sectional area of pin (1700N/A = 8MN/m^2). Solve for A, then diameter; watch units and decimal point. Please ask again if you don't understand the concept of double shear.

mate i totally understand it now ..