Solve Two Physics Problems: Ebonite Rod & Electroscope

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SUMMARY

The discussion addresses two physics problems involving charge distribution. The first problem calculates the charge on a pith ball after it shares an excess of 6.4 x 108 electrons from an ebonite rod. The charge on the pith ball is determined to be 1.024 x 10-10 coulombs. The second problem involves the charge acquired by the Earth when 2.5 x 1011 electrons leave a grounded metal-leaf electroscope, resulting in a charge of -4.005 x 10-8 coulombs.

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  • Familiarity with the charge of an electron (-1.602 x 10-19 coulombs)
  • Ability to perform calculations involving scientific notation
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Skipperchrldr
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Hey everyone! I was wondering if someone could help me with these two physics problems i have to turn in tomorrow. Here's the first:
An ebonite rod with an excess of 6.4 X 10^8 electrons shares its charge equally with a pith ball when they touch. What is the charge on the pith ball, in coulumbs?

Here's the second:
How much charge does the Earth acquire if 2.5 x 10^11 electrons leave a grounded metal-leaf electroscope?
 
Physics news on Phys.org
The charge of an electron is -1.602 x 10^-19 coloumbs.

cookiemonster
 

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