LaGrange Error and power series

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SUMMARY

The discussion centers on calculating the truncation error using the LaGrange error formula for the power series approximation of the function 1/(1-x^2) with the polynomial 1 + x^2 + x^4 + x^6 over the interval (-1, 1). The LaGrange error formula is defined as E ≤ M/(n+1)! |x-a|^(n+1), where M represents an upper bound on the (n+1)th derivative. Participants suggest using n+1=7 or substituting x^2 with y and using n+1=4 to simplify the calculation.

PREREQUISITES
  • Understanding of power series and polynomial approximations
  • Familiarity with the LaGrange error formula
  • Knowledge of derivatives and their applications in error analysis
  • Basic calculus concepts, particularly Taylor series
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  • Study the derivation and applications of the LaGrange error formula
  • Explore polynomial approximations and their convergence properties
  • Learn about Taylor series and their role in function approximation
  • Investigate upper bounds for derivatives in error analysis
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Students in calculus or numerical analysis, educators teaching approximation methods, and anyone interested in understanding error analysis in mathematical approximations.

SoaringQuail
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There's a homework problem that I've been struggling over:

Find a formula for the truncation error if we use 1 + x^2 + x^4 +x^6 to approximate 1/(1-x^2) over the interval (-1, 1).

Now, I assume that you need to use LaGrange error but I'm not sure how to proceed. Any help would be greatly appreciated.
 
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SoaringQuail said:
There's a homework problem that I've been struggling over:

Find a formula for the truncation error if we use 1 + x^2 + x^4 +x^6 to approximate 1/(1-x^2) over the interval (-1, 1).

Now, I assume that you need to use LaGrange error but I'm not sure how to proceed. Any help would be greatly appreciated.

Since you mention LaGrange error, presumably you know the formula for it! Off the top of my head, I believe it is
E\le \frac{M}{(n+1)!}|x-a|^{n+1}
where M is an upper bound on the n+ 1 derivative. Here, by the way, you can take either n+1= 7 or replace "x2" by "y" and use n+1= 4 with the formula in y.
 

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